(x^2+x+3)(x-3)=0

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Solution for (x^2+x+3)(x-3)=0 equation:


Simplifying
(x2 + x + 3)(x + -3) = 0

Reorder the terms:
(3 + x + x2)(x + -3) = 0

Reorder the terms:
(3 + x + x2)(-3 + x) = 0

Multiply (3 + x + x2) * (-3 + x)
(3(-3 + x) + x(-3 + x) + x2(-3 + x)) = 0
((-3 * 3 + x * 3) + x(-3 + x) + x2(-3 + x)) = 0
((-9 + 3x) + x(-3 + x) + x2(-3 + x)) = 0
(-9 + 3x + (-3 * x + x * x) + x2(-3 + x)) = 0
(-9 + 3x + (-3x + x2) + x2(-3 + x)) = 0
(-9 + 3x + -3x + x2 + (-3 * x2 + x * x2)) = 0
(-9 + 3x + -3x + x2 + (-3x2 + x3)) = 0

Combine like terms: 3x + -3x = 0
(-9 + 0 + x2 + -3x2 + x3) = 0
(-9 + x2 + -3x2 + x3) = 0

Combine like terms: x2 + -3x2 = -2x2
(-9 + -2x2 + x3) = 0

Solving
-9 + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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